If a funicular diagram is drawn for a system of forces which are in equilibrium, it will be found that not only does the force diagram form a closed polygon, but that also the two end strings of the funicular diagram will be colinear, forming a closed funicular polygon, as shown in Fig. 1.

Thus it may be said that the graphical conditions of equilibrium are that both the force polygon and the funicular polygon should close. The closure of the force polygon means that
We may use the fact that the two diagrams must close to obtain a graphical solution for equilibrium problems, as can be seen from the following example.
Example. Find graphically the reaction forces at

Solution. A free-body diagram of the truss with the forces identified by means of Bow’s Notation is shown in Fig. 3. The unknown forces

In Fig. 4 we show as much of the force and funicular polygons as can be drawn with the known forces. The complete solution to scale is shown in Fig. 5.

It will be seen from the force polygon of Fig. 4 that it is possible to solve for one of the unknown forces,

Scaling off the values of the forces, we find:
To check our solution, let us determine the force
6.7.1 Problems
1. A beam is supported at two points and is loaded by three parallel forces as shown in the diagram. Find graphically the two reactions at the supports.

Answer
2. A system of three parallel forces acts on a beam supported as shown in the figure. Find graphically the two reactions at the supports. Check these reactions analytically.

Answer
200 lb (down); 8200 lb (up)
3. A truss is loaded by three forces as shown in the diagram. Find graphically the forces at the supports. Check the value of the vertical reaction at the right end of the truss analytically.

Answer
2150 lb (right end)