“Imaginaries” emerged in algebra as early as the Middle Ages when mathematicians sought a general solution of quadratic equations. The choice of the word "imaginary" is unfortunate, but it indicates the distrust in which complex numbers were held. These unwarranted suspicions were finally dispelled at the end of the 18
Table of Contents
1.1.1 Definition of Complex Number
To the set of real numbers we adjoin a new symbol
Sums and products of complex numbers are clearly given by the formulae
If
Every complex number
With every complex number
It is possible to give a complete axiomatic definition of complex number without introducing the auxiliary symbol
A complex number is defined as a pair of real numbers
1.1.2 The Complex Number Plane
The complex numbers may be represented geometrically by the points of an ordinary cartesian plane – each complex number
Each point of the complex plane determines a vector (directed line segment) from the origin to the point. Since addition of two complex numbers is performed by addition of their
It is natural to introduce polar coordinates
\begin{align} \tag{1.21} r = \sqrt{x^{2}+y^{2}} = |z|\ ;\\ \quad x=r \cos\theta, \quad y=r \sin\theta. \end{align} Using these relations we may write
The conjugate
The product of two complex numbers is mot simply expressed in polar form: \begin{align} \tag{1.24} z_{1} z_{2} &= r_{1} r_{2}\big[\left(\cos \theta_{1} \cos \theta_{2}-\sin \theta_{1} \sin \theta_{2}\right)\\ & \qquad + i\left(\cos \theta_{1} \sin \theta_{2}+\cos \theta_{2} \sin \theta_{1}\right)\big]\\ &= r_{1} r_{2}\big[\cos \left(\theta_{1}+\theta_{2}\right)+i \sin \left(\theta_{1}+\theta_{2}\right)\big]. \end{align}
This verifies the relation
If
In conclusion we prove an important inequality which we shall use very frequently; it is known as the triangle inequality :
Exercises
Exercise 1.1 . Prove by mathematical induction the following consequence of De Moivre’s formula
Exercise 1.2 . Prove the identity
Exercise 1.3 . Write the following expressions in standard form
Exercise 1.4 . In
1.1.3 The Complex Number Sphere; Stereographic Projection
For certain purposes it is simpler to represent complex numbers by the points on a sphere rather than those of a plane. To this end we use the unit sphere :
The ray which joins each point
Stereographic Projection
This mapping of the sphere onto the plane is the familiar stereographic projection of the cartographers who, in view of its special properties, find it indispensable for navigational maps. Before we consider these properties let us formulate the analytical description of the mapping:
By elementary geometry we obtain relations between
Stereographic projection is characterized by the following property:
Every circle in the
If a straight line is regarded as a special kind of circle, namely, a "circle" through the point at infinity, we may express the theorem simply:
Theorem 1.1 . Stereographic projection preserves circles.
Proof. Let
The mapping defined by stereographic projection is conformal or angle-preserving . By this we mean that the images on the sphere of any two intersecting curves have the same angle of intersection as the original curves. The proof of conformality can be demonstrated analytically. Here we give a simple geometrical argument.
Let
Exercises
Exercise 1.5 . Show that the segment joinint two points
Exercise 1.6 . Show that the endpoints
Exercise 1.7 . Characterize the image on the sphere under stereographic projection of
- A family of parallel lines
- A pencil of lines
- A set of concentric circles
Also characterize the image in the
Exercise 1.8 . Give a geometrical proof of conformality by investigating the image of the pencil of circles passing through the north pole and a fixed point
1.1.4 Point Sets
With the geometrical interpretation of complex numbers in mind we shall consider a number of useful concepts of point set theory.
A set
An
An open set is a set which consists entirely of interior points. If the set
A set
A point
Theorem 1.2 (The Bolzano-Weierstrass Theorem.). Every bounded infinite set of points of the complex plane possesses at least one accumulation point.
Another important result is the Heine-Borel Covering Theorem .
Theorem 1.3 . If to each point of a bounded closed set
Exercises
Exercise 1.9 . Show that a neighborhood of a point is an open set.
Exercise 1.10 . Show that a closed set contains all its accumulation points and, conversely, that any set which contains all its accumulation points is closed.
Exercise 1.11 . Prove that the boundary of any set is closed.
Exercise 1.12 . Demonstrate that a region is a closed set.