Quick Reference
In this section we will learn how to multiply two polynomials.
| Method | Best used for | Core idea |
|---|---|---|
| Distributive property | Multiplication of any two polynomials | Multiply each term of the first by each term of the second |
| FOIL | Multiplication of two binomials only | First, Outer, Inner, Last |
| Long (vertical) method | Multiplication of three or more terms | Align partial products by degree in columns |
The Rule
To multiply two polynomials, apply the distributive property by multiplying each term of the first polynomial by each term of the second. Then use the exponent rule
and collect any like terms.
Product of Two Monomials
To multiply two monomials, multiply the coefficients and add the exponents:
Product of a Monomial and a Polynomial
Use the distributive property to multiply the monomial by each term of the polynomial:
Product of Two Polynomials
Distribute each term of the first polynomial across all terms of the second, then collect like terms. For example, to expand , distribute and then :
\begin{aligned} 3x(2x^2-3x+4) &= 6x^3-9x^2+12x \\ -2(2x^2-3x+4) &= -4x^2+6x-8 \end{aligned}Adding the results:
Example 1. Multiply .
Solution
\begin{aligned} (4x^{2}-3x+5)(2x^{3}-x) &= 4x^{2}(2x^{3}-x)-3x(2x^{3}-x)+5(2x^{3}-x) \\ &= (8x^{5}-4x^{3})-(6x^{4}-3x^{2})+(10x^{3}-5x) \\ &= 8x^{5}-6x^{4}+(-4+10)x^{3}+3x^{2}-5x \\ &= 8x^{5}-6x^{4}+6x^{3}+3x^{2}-5x \end{aligned}Degree of the Product
If is a polynomial of degree and is a polynomial of degree , then the product is a polynomial of degree :
In Example 1, has degree $2$ and has degree $3$; the product has degree , as expected.
Long Multiplication
When multiplying polynomials with three or more terms, a structured layout analogous to long multiplication of integers is often cleaner and less error-prone. The procedure is:
- Arrange both polynomials in descending order of degree. Write the one with more terms on top (the multiplicand).
- Form partial products: multiply the multiplicand by each term of the multiplier separately, writing each result on its own row.
- Align by degree: place each partial product so that terms of the same degree sit in the same column.
- Add column by column to obtain the final result.
Key tip: if the multiplicand is missing a term of some degree, that column is simply left blank (or filled with $0$) to keep the alignment correct.
Example 2. Multiply by .
Solution
Arrange in descending order and form the three partial products: \begin{aligned} x^2\cdot(2x^3-x^2+5) &= 2x^5-x^4+5x^2 \\ x\cdot(2x^3-x^2+5) &= 2x^4-x^3+5x \\ (-3)\cdot(2x^3-x^2+5) &= -6x^3+3x^2-15 \end{aligned} Add the partial products, aligning by degree: Therefore,Example 3. Multiply by using the long multiplication method.
Solution
The multiplier has no or constant term, so those columns are empty: \begin{aligned} 2x^3\cdot(4x^2-3x+5) &= 8x^5-6x^4+10x^3 \\ (-x)\cdot(4x^2-3x+5) &= -4x^3+3x^2-5x \end{aligned} Adding: Therefore, , confirming Example 1.FOIL Method for Multiplying Binomials
When multiplying two binomials, a helpful mnemonic called FOIL organizes the four products that arise from the distributive property. FOIL stands for First, Outer, Inner, Last.
Consider two binomials and where and represent any algebraic terms. For example, in (3x-2)(-2x^2+5x), we have , , , and .The four FOIL products are:
- F (First): Multiply the first terms of each binomial: .
- O (Outer): Multiply the outer terms: .
- I (Inner): Multiply the inner terms: .
- L (Last): Multiply the last terms: .
Adding all four products: .

Example 4. Multiply using the FOIL method.
Solution
- F (First):
- O (Outer):
- I (Inner):
- L (Last):
Example 5. Multiply using the FOIL method.
Solution
- F (First):
- O (Outer):
- I (Inner):
- L (Last):
FOIL is a useful mnemonic for binomials, but it is simply the distributive property in disguise. The core rule is always to multiply every term in the first polynomial by every term in the second. For polynomials with more than two terms, FOIL does not directly apply; use the distributive property or the long multiplication method instead.
Determining Coefficients in the Product
Consider the product of a degree-3 polynomial by a degree-2 polynomial:
\begin{aligned} &(a_3x^3+a_2x^2+a_1x+a_0)(b_2x^2+b_1x+b_0) \\ &= a_3b_2\,x^5+(a_3b_1+a_2b_2)x^4+(a_3b_0+a_2b_1+a_1b_2)x^3 \\ &\quad+(a_2b_0+a_1b_1+a_0b_2)x^2+(a_1b_0+a_0b_1)x+a_0b_0. \end{aligned}The product has degree , and a clear pattern governs each coefficient:
The coefficient of in the product is the sum of all products where , with ranging over the degrees present in the first polynomial and over those in the second.
For example, to get the coefficient of , collect all pairs with : they are $(3,0)$, $(2,1)$, and $(1,2)$, giving .
This rule applies to the product of any two polynomials
and provides an efficient way to find any single coefficient without expanding the entire product.
Example 6. Find the coefficient of in the product
Solution
The degree of the product is . For the term , we need with and . The largest possible is $75$ (giving ) and the smallest is (giving ). So ranges from $40$ to $75$, and the coefficient of is For comparison, the leading coefficient of the product (coefficient of ) has only one contributing pair, and , so it equals .Example 7. Find the coefficient of in the product
Solution
We need all pairs with , where and :| $3$ | $0$ | $6$ | ||
| $2$ | $1$ | $1$ | $6$ | $6$ |
| $1$ | $2$ | $5$ | ||
| $0$ | $3$ | $7$ | $2$ | $14$ |
Frequently Asked Questions